# Finding the total vertical distance - transverse wave

by PhysicsFriend
Tags: distance, transverse, vertical, wave
 P: 4 1. The problem statement, all variables and given/known data Suppose the amplitude and frequency of the transverse wave in the figure are, respectively, 5.89 cm and 5.00 Hz. Find the total vertical distance (in cm) through which the colored dot moves in 3.00 s. http://i45.tinypic.com/3007ihy.png 2. Relevant equations y = A sin (2pi x f x t - (2pi x)/λ) v=λf v= x/t 3. The attempt at a solution x=vt λ=v/f x/λ = vt/ (v/f) = t x f = 15 Plug in x/λ = 15 Plug in A = .0589m Plug in f = 5 Hz Plug in t = 3.00 seconds Answer = 0m However, the online system says it is incorrect. I have no other strategy besides this one? Can someone help?
 Thanks PF Gold P: 4,577 You have found the displacement. Which is zero, because in 3.00 seconds the dot makes a few COMPLETE oscillations and returns where it was. You need to find the distance, which is the length of the total path the dot has gone through.
 P: 4 OH y = displacement and not distance! Got it. Thanks so much!

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