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Finding the total vertical distance - transverse wave |
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| Jan29-13, 08:25 AM | #1 |
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Finding the total vertical distance - transverse wave
1. The problem statement, all variables and given/known data
Suppose the amplitude and frequency of the transverse wave in the figure are, respectively, 5.89 cm and 5.00 Hz. Find the total vertical distance (in cm) through which the colored dot moves in 3.00 s. http://i45.tinypic.com/3007ihy.png 2. Relevant equations y = A sin (2pi x f x t - (2pi x)/λ) v=λf v= x/t 3. The attempt at a solution x=vt λ=v/f x/λ = vt/ (v/f) = t x f = 15 Plug in x/λ = 15 Plug in A = .0589m Plug in f = 5 Hz Plug in t = 3.00 seconds Answer = 0m However, the online system says it is incorrect. I have no other strategy besides this one? Can someone help? |
| Jan29-13, 08:53 AM | #2 |
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You have found the displacement. Which is zero, because in 3.00 seconds the dot makes a few COMPLETE oscillations and returns where it was. You need to find the distance, which is the length of the total path the dot has gone through.
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| Jan29-13, 12:34 PM | #3 |
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OH
y = displacement and not distance! Got it. Thanks so much! |
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