
#1
Feb1813, 09:08 PM

P: 249

So apparently a neutral pion is a superposition of [itex]u\bar{u}[/itex] and [itex]d\bar{d}[/itex]. I'm having trouble understanding what this means. I have no problem understanding how the decay products of some scattering experiment could be a superposition of these two states, but how can we treat this superposition as a single particle? And how would you draw the feynman diagram for some process involving a neutral pion?




#2
Feb1813, 10:12 PM

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PF Gold
P: 11,025

The neutral pions are decay products from scattering.
There are plenty of examples online of Feynman diagrams involving pions. 



#3
Feb1913, 06:37 AM

P: 977

the decay of neutral pions into two photons happens through the anomaly in divergence of axial vector current.the decay has a triangle diagram.
http://prola.aps.org/abstract/PR/v177/i5/p2426_1 it is available freely here. http://astrophysics.fic.uni.lodz.pl/...pdf/12/068.pdf 


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