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Neutral pions

by dEdt
Tags: neutral, pions
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dEdt
#1
Feb18-13, 09:08 PM
P: 282
So apparently a neutral pion is a superposition of [itex]u\bar{u}[/itex] and [itex]d\bar{d}[/itex]. I'm having trouble understanding what this means. I have no problem understanding how the decay products of some scattering experiment could be a superposition of these two states, but how can we treat this superposition as a single particle? And how would you draw the feynman diagram for some process involving a neutral pion?
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Simon Bridge
#2
Feb18-13, 10:12 PM
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The neutral pions are decay products from scattering.
There are plenty of examples online of Feynman diagrams involving pions.
andrien
#3
Feb19-13, 06:37 AM
P: 1,020
the decay of neutral pions into two photons happens through the anomaly in divergence of axial vector current.the decay has a triangle diagram.
http://prola.aps.org/abstract/PR/v177/i5/p2426_1
it is available freely here.
http://astrophysics.fic.uni.lodz.pl/...pdf/12/068.pdf


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