# Superposition Question

by timtng
Tags: superposition
 P: 26 A transverse wave of frequency 40 Hz propagates down a string. Two points 5 cm apart are out of phase by p/6. (a) What is the wavelength of the wave? (b) At a given point, what is the phase difference between two displacements for times 5 ms apart? (c) What is the wave velocity? for a.) I use theta=(sπx)/λ solving for λ I get λ=.6m Please help me on part b and c, and check to see if I did part a correctly.
 Emeritus Sci Advisor PF Gold P: 10,424 For part b, you can figure out the phase difference by looking at the frequency of the wave. The frequency is 40 Hz, so the wave has a period T = 1/40 Hz = 0.025 s. The time period 50 ms is thus 0.050 / 0.025 = 2 periods, exactly. If the point on the string executes exactly an integer number of periods in 50 ms, then its phase difference between the beginning and end of that 50 ms period is zero. For part c, you know the frequency, 40 Hz, and the wavelength, 0.6 m. You can find the velocity with $$v = \lambda \cdot \nu$$ Does this make sense? - Warren

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