Superposition Question


by timtng
Tags: superposition
timtng
timtng is offline
#1
Dec4-03, 02:00 PM
P: 26
A transverse wave of frequency 40 Hz
propagates down a string. Two points 5 cm apart are
out of phase by p/6. (a) What is the wavelength of the
wave? (b) At a given point, what is the phase
difference between two displacements for times 5 ms
apart? (c) What is the wave velocity?

for a.) I use theta=(sπx)/λ
solving for λ I get λ=.6m

Please help me on part b and c, and check to see if I did part a correctly.
Phys.Org News Partner Science news on Phys.org
Going nuts? Turkey looks to pistachios to heat new eco-city
Space-tested fluid flow concept advances infectious disease diagnoses
SpaceX launches supplies to space station (Update)
chroot
chroot is offline
#2
Dec4-03, 02:33 PM
Emeritus
Sci Advisor
PF Gold
chroot's Avatar
P: 10,424
For part b, you can figure out the phase difference by looking at the frequency of the wave. The frequency is 40 Hz, so the wave has a period T = 1/40 Hz = 0.025 s. The time period 50 ms is thus 0.050 / 0.025 = 2 periods, exactly. If the point on the string executes exactly an integer number of periods in 50 ms, then its phase difference between the beginning and end of that 50 ms period is zero.

For part c, you know the frequency, 40 Hz, and the wavelength, 0.6 m. You can find the velocity with

[tex]v = \lambda \cdot \nu[/tex]

Does this make sense?

- Warren


Register to reply

Related Discussions
Superposition / Wave Question Introductory Physics Homework 2
Superposition circuit question..please help out! Advanced Physics Homework 3
Weird Superposition Question Introductory Physics Homework 1
Proving the superposition of initial conditions gives superposition of motion Introductory Physics Homework 2