Appearance of light cones in curved spacetimes
Hi again, Jennifer,
MeJennifer said:
A common phrase used to show alleged time travel solutions in GR. Even a person like Kip Thorne uses it.
But my question is, is that an accurate representation of GR in strong gravitational fields?
It is when Kip Thorne uses it! :-/ I know that because he can provide a correct figure which conforms to this informal description, as I can verify using my own computations.
I prefer to be more specific about this "tipping". I guess you are talking about light cones in the Boyer-Lindquist chart for the Kerr vacuum solution in gtr, which does feature closed timelike curves in the interior region, or light cones in the Goedel lambdadust solution, which also features closed timelike curves (see for example the beautiful figures in Hawking and Ellis, Large Scale Structure of Space-Time, for both of these examples).
But let's study an even simpler example:
MeJennifer said:
The Schwarzschild metric expressed using the Eddington-Finkelstein coordinates show those "light cones tipping over", and eventually the radial and time coordinates reverse.
Specifically, consider the advanced (infalling) Eddington chart, in which the line element takes the form
ds^2 = -(1-2 m/r) \, du^2 + 2 \, du \, dr + r^2 \, \left( d\theta^2 + \sin(\theta) \, d\phi^2 \right),
-\infty < u < \infty, \; 0 < r < \infty, \; 0 < \theta < \pi, \; -\pi < \phi < \pi
We can write down a "frame field" consisting of four orthonormal vector fields, a timelike unit vector
\vec{e}_1 = \partial_u - m/r \, \partial_r
plus three spacelike unit vectors
\vec{e}_2 = \partial_u - (1-m/r) \, \partial_r
\vec{e}_3 = 1/r \, \partial_\theta
\vec{e}_4 = 1/r/\sin(\theta) \, \partial_\phi
You can use these to draw the light cones. If you do it right, they will all be tangent to the null vector field \partial_r and as r decreases, they lean inwards, until at r=2 m they are also tangent to \partial_u.
MeJennifer said:
eventually the radial and time coordinates reverse.
Many people, even some who ought to know better, do talk that way, and invariably they wind up confusing everyone, including themselves. What they should really say is that the vectors \partial_u are timelike outside the horizon, null at the horizon, and spacelike inside the horizon. Nothing "reverses"; in particular, the frame vectors given above are unambiguously timelike throughout (for the first) or spacelike throughout (for the remaining three).
George Jones is completely correct: of course "time and space" do not "swap roles" inside the horizon, that would be nonsense!
To elaborate on one point he alluded to, the coordinate basis vector field \partial_u happens to be a Killing vector field; that is, the Schwarzschild vacuum is invariant under time translation. Similarly, the coordinate basis vector \partial_\phi is a spacelike Killing vector whose integral curves are circles; that is, the Schwarzschild vacuum is invariant under rotation about the axis r=0.
The fact that in the exterior we have an irrotational timelike Killing vector and a spacelike Killing vector (whose integral curves are circles) means that the exterior region is static and axisymmetric. (This is also true of the Kerr vacuum solution.) Inside, we have two spacelike Killing vectors, but no timelike Killing vector; the solution is NOT static inside the horizon. Of course not, since otherwise an observer could use his rocket engine to hover at some Schwarzschild radius 0 < r < 2m.
MeJennifer said:
But this reversal, and even the tipping over seems to me a peculiarity of the choice of coordinates. It seems to me that it is assumed that there is a particular relationship between the radial and time coordinate.
Not sure I understand that, but it sounds like you did correctly recognize that the coordinate basis vector \partial_u changes character at the horizon.
Hope this helps,
Chris Hillman