PH question, I really don't get this

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Discussion Overview

The discussion revolves around calculating the concentration of hydronium ions ([H3O+]) in acid rain given its pH of 4.23. The context is a homework problem involving the application of pH and related equations.

Discussion Character

  • Homework-related

Main Points Raised

  • One participant presents the homework statement and relevant equations for calculating [H3O+].
  • Another participant asks for clarification on which equation to use for the calculation.
  • A participant indicates understanding that the first equation is necessary but expresses confusion about performing the reverse calculation.
  • One participant provides the formula for calculating [H3O+] based on pH, suggesting that H3O+/H+ can be expressed as 10^(-pH).
  • Several participants express difficulty with using their calculators to compute the value.
  • Ultimately, one participant reports successfully finding the answer after receiving assistance.

Areas of Agreement / Disagreement

The discussion appears to be primarily focused on clarifying the calculation method, with participants generally agreeing on the approach but expressing varying levels of understanding and comfort with the calculator usage.

Contextual Notes

Some participants demonstrate uncertainty regarding the calculator functions needed to perform the calculations, indicating a potential limitation in their mathematical skills or familiarity with the tools.

Who May Find This Useful

Students working on chemistry problems related to pH and hydronium ion concentration, particularly those seeking help with calculator usage in scientific calculations.

night nurse 991
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Homework Statement


What is the [H3O+] of acid rain with a pH of 4.23?


Homework Equations


pH = -log[H30+]
pOH = -log[OH-]
pH + pOH = 14


The Attempt at a Solution



the four possible choices are
a. 1.7 x 10^-10
b. 5.8 x 10^-5
c. 2.3 x 10^-4
d. 1.7 x 10^5
 
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You are given the pH and need to calculate the concentration of the H_{3}O^+ ions. Which equation should you use?
 
I know I have to use the first one but I don't know how to do the reverse of it
 
Since pH = -log[H30+] or pH = -log[H+]
H3O+/H+ = 10^(-pH)
 
Last edited:
But I don't get how to plug it in on my calculator
 
night nurse 991 said:
But I don't get how to plug it in on my calculator

10^(-pH)
10 to the -pH power.
 
Oh okay I got the answer thank you so much!
 

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