Differentation Problem (involves product rule)

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Homework Help Overview

The discussion revolves around differentiating a function defined as the product of three linear factors: F(x) = (x-1)(x-2)(x-3). Participants are exploring methods for applying the product rule in this context, as well as alternative approaches to differentiation.

Discussion Character

  • Exploratory, Conceptual clarification, Mathematical reasoning

Approaches and Questions Raised

  • The original poster attempts to understand how to apply the product rule to three factors, expressing uncertainty about the process. Some participants suggest rewriting the function to simplify the differentiation process. Others provide a formula for differentiating a product of three functions and share insights on expanding the function before differentiation.

Discussion Status

Participants are actively discussing different methods for differentiating the function, including the use of the product rule and expansion. There is a mix of suggestions and approaches being explored, with no explicit consensus reached on the best method.

Contextual Notes

Some participants reference tools like Maple for verification of results, indicating a reliance on computational assistance in their reasoning. The original poster's request for a basic overview suggests a need for foundational understanding in differentiation techniques.

Cod
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Here's the equation:

F(x) = (x-1)(x-2)(x-3)


I know how to diff. using the product rule when you only have 2 equations, but not 3.I looked at the examples in my book and none of them show how you would work out this sort of problem. So if someone could give me the basic overview of how to differentiate a problem like this, I'd greatly appreciate it.
 
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Just wondering something...

Could I change the equation to read like this before diff. it:

F(x) = (x-1)(x^2-5x+6) ?



Then I could just use the product rule from there.
 
Last edited:
consider u,v,w as a function of x

then [tex]\frac{d}{dx}uvw = uv \frac{d}{dx}w + vw\frac{d}{dx}u + uw\frac{d}{dx}v[/tex]
 
Just expand it then differentiate. According to Maple, you get the same answer.


Here is when you differentiate 3 terms

> R3 := diff((x-1)*(x-2)*(x-3),x);

R3 := (x - 2) (x - 3) + (x - 1) (x - 3) + (x - 1) (x - 2)

> R4 := expand(R3);
R4 := 3 x^2 - 12 x + 11


Here is when you expand it then differentiate it

R1 := expand((x-1)*(x-2)*(x-3));
R1 := x^3 - 6 x^2 + 11 x - 6

> R2 := diff(R1,x);
R2 := 3 x^2 - 12 x + 11



You end with the same answer. Just expand it; it's much easier.
 

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