# Inertial and Non-Inertial Frames of Reference Question

by Kaos_Griever
Tags: frames, inertial, noninertial, reference
 Mentor P: 41,318 Your solution is fine! FYI, here's how I would do it: Horizontal forces: $$T\sin\theta = ma$$ Vertical forces: $$T\cos\theta = mg$$ Combine (divide one by the other) to get: $$a = g\tan\theta$$