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Electron drift speed in a copper wire. 
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#1
Apr807, 04:41 PM

P: 30

I'm really stuck on this one problem:
"A small but measurable current of 4.20E10 A exists in a copper wire whose diameter is 0.02 cm. Calculate the electron drift speed (in meters/second)." Source: Serway and Jewett I know that: I = 4.20E10 A n = 8960 kg/m^3 q = 1.6E19 C d = 2E4 m J = (I/A) = n x q x v Thus, v = I/(n x q x A) What does A stand for and how would I go about finding it? Also, am I converting things correctly and using the proper value for the density? Any help would be greatly appreciated. 


#2
Apr807, 04:48 PM

P: 37

A is the crosssectional area of the wire.



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