Redox Balancing

jesuslovesu

1. The problem statement, all variables and given/known data
Cl2 -> Cl- + ClO3-
(in basic solution)

2. Relevant equations



3. The attempt at a solution
Well, I've tried messing around with the half reactions but since Cl2 is involved in both, they don't seem to do much good.

e + Cl2 -> Cl-
Cl2 -> ClO3- + 5e

Normally, I would multiply the top by 5e to let the electrons cancel, but then there's a Cl2 and a 5Cl2 so that doesn't appear to work...

Anyone have any ideas on how to do this?

Borek

You are on the right track - Cl2 and a 5Cl2 is 6Cl2

Just be careful when balancing half reactions.

Borek
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