Cylinder about side, finding angular velocity....

aliaze1

1. The problem statement, all variables and given/known data

A 5.0 kg, 60-cm-diameter disk rotates on an axle passing through one edge. The axle is parallel to the floor. The cylinder is held with the center of mass at the same height as the axle, then released.

http://session.masteringphysics.com/...gure_13_72.jpg

What is the cylinder's angular velocity when it is directly below the axle?

2. Relevant equations

Law of conservation of energy (kinetic and potential of both sides)

3. The attempt at a solution

I tried to do this problem using mgy=1/2mv^2 but it didnt work...

I know it has something to do with moment of inertia, but do I just add the moment of inertia to the 1/2mv^2 and solve for v?

hage567

Use rotational energy with the potential energy. The initial rotation energy about the axle is zero, so all the potential energy must go into rotational energy at the bottom point.
You do not just "add" in moment of inertia! You will need to find the moment of inertia of the disk about that pivot point.

aliaze1

ah ic, i need to use rotational energy...i was treating this as a pendulum but i guess i cant do that haha

lol yea, thats what i meant, i have to use Icm + Md^2 to find it at the pivot point

thanks, ill see how it goes

aliaze1

yo thanks, i got it!