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Solving quadratic congruences

 
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Oct12-07, 06:21 PM   #1
 

Solving quadratic congruences


1. The problem statement, all variables and given/known data

Hello everyone!

How would you solve a quadratic or nth degree congruence? For example how would I solve:


(x^2) + 2x -3 = 0 (mod 8 )


3. The attempt at a solution

I know this can be written like:

(x^2) + 2x = 3 (mod 8 ) but where would I go from here? and would I use the same approach for nth degree congruencies?

Thanks
 
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Oct12-07, 10:27 PM   #2

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I don't think there is any approach for nth degree congruencies. mod 8 there are only 8 candidates for x. I suggest you try them all.
 
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