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Finding distance with a pivot |
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| Oct18-07, 10:29 PM | #1 |
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Finding distance with a pivot
1. The problem statement, all variables and given/known data
The two objects in the figure below are balanced on the pivot, with m = 1.8 kg. What is the distance d? http://i241.photobucket.com/albums/f.../p13-27alt.gif 2. Relevant equations 3. The attempt at a solution I haven't attempted a solution because I'm not sure how to set this problem up. I know that a Fnet must be found, and I know that the two masses would be in the equation and I know that the pivot would exert a normal force. I know part of the equation would be Fnet = N(pivot) - (m1 + m2)g, but where do the distances come into play? |
| Oct18-07, 10:46 PM | #2 |
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| Oct18-07, 10:48 PM | #3 |
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No I'm not.
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| Oct18-07, 11:06 PM | #4 |
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Finding distance with a pivot
Torque of a mass about a point is just its weight times the perpendicular distance of its cg to the point. The torque of each mass must then balance. You'll have to draw a good sketch to get the proper distances involved.
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| Oct18-07, 11:11 PM | #5 |
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I have no idea how to do that.
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