## Factoring cubic equation

Anyone here know how to factor this equation?

1. The problem statement, all variables and given/known data

$$a^{3}c-a^{3}b+b^{3}a-b^{3}c+c^{3}b-c^{3}a$$

3. The attempt at a solution

I tried factoring by grouping but ended up getting nowhere.

If anyone can factor this equation, please tell me step by step how you got it.
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 Recognitions: Gold Member Science Advisor Staff Emeritus Cubics are bad enough but this has 3 variables. This is not a complete factorization but I think the most simplified form is $$(a^3c- ac^3)+ (b^3a- a^3b)+ (c^3b- b^3c)= ac(a^2- c^2)+ ab(b^2- a^2)+ bc(c^2- b^2)$$ $$= ac(a- c)(a+ c)+ ab(b- a)(b+ a)+ bd(c- b)(c+ b)$$
 thanks, that will be ok. but if you could figure how to get this form, please let me know. $$(a+b+c)(b-c)(c-a)(a-b)$$

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## Factoring cubic equation

Notice the symmetry in the variables. Then, without loss of generality, treat it as a polynomial in a, and collect coefficients.
 Yeah, I'd have to agree with Gib Z

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