
#1
Jan2308, 04:51 PM

P: 287

I'm having problems with the work section of my calc book. This is the problem:
If 6 J of work is needed to stretch a spring from 10 cm to 12 cm and another 10 J is needed to stretch from 12 cm to 14 cm, what is the natural length of the spring? I set up two equations: 6 J= Kx^2/2 evaluated at 10L and 12L 10 J= Kx^2/2 evaluated at 12L and 14L I'm not sure what to do after the mess hell of algebra, I end up with a K and an L. Do I solve for K in one equation and plug it into the other? 



#2
Jan2308, 05:36 PM

P: 287

I got a length of 8




#3
Jan2308, 05:39 PM

Math
Emeritus
Sci Advisor
Thanks
PF Gold
P: 38,879

If that's the easiest way to solve the two equations. Any any case, you want to eliminate K from the equations, resulting in single equation for L.



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