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really a virtual particle sea? |
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| Mar8-08, 04:04 AM | #1 |
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really a virtual particle sea?
I've often heard the argument that vacuum is full of virtual particle pairs that get created and annihilated, but in fact the ground state of the harmonic oscillator is orthogonal to all excitation states, so shouldn't the vacuum, when in ground state, actually be empty of all particles? What is this virtual particle sea stuff really?
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| Mar8-08, 03:24 PM | #2 |
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It was Dirac who came up with the idea that the vacuum was filled with virtual positron and electron pairs (the reason that they were pairs has to do with conservation laws like that of electrical charge). You can break up such a pair and make the particles real when you have enough energy coming from some interaction between two charged particles that were placed inside the vaccuum. |
| Mar8-08, 06:08 PM | #3 |
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I understand that when an oscillator is in ground state, there is a nonzero probability to observe it arbitrarily far from the origo. For example, in vacuum there is a nonzero probability for fields to have arbitrarily large values. I've thought that this is quantum fluctuation.
However, I don't understand how an oscillator, when in ground state, could have a nonzero probability to be on an excitation state! Orthogonal is orthogonal: Zero overlapping.
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| Mar8-08, 07:39 PM | #4 |
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really a virtual particle sea? |
| Mar9-08, 12:21 AM | #5 |
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look up 'dielectric'.
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| Mar9-08, 05:51 AM | #6 |
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marlon |
| Mar9-08, 06:39 AM | #7 |
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| Mar9-08, 06:53 AM | #8 |
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When a system is on an energy eigenstate [itex]|\psi_n\rangle[/itex] corresponding to an energy [itex]E_n[/itex], then according to the SE the time evolution is trivial phase rotation
[tex] |\psi(t)\rangle = e^{-i(t-t_0)E_n/\hbar}|\psi_n\rangle. [/tex] I have never seen Heisenberg uncertainty principle [tex] \Delta E\;\Delta t \geq \hbar [/tex] used in arguing that there would be some fluctuation in the time evolution of a system. It is always the phase rotation only. |
| Mar9-08, 10:36 AM | #9 |
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Recognitions:
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Regards, Reilly Atkinson ' |
| Mar9-08, 12:40 PM | #10 |
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marlon |
| Mar10-08, 04:18 AM | #11 |
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Nevertheless, in the vacuum the value of the field, and consequently the value of energy, is uncertain. Consequently, the average energy is larger than zero. See also http://xxx.lanl.gov/abs/quant-ph/0609163 [Found. Phys. 37 (2007) 1563] especially Sec. 9.3. |
| Mar13-08, 04:43 PM | #12 |
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marlon |
| Mar14-08, 05:20 AM | #13 |
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is what you wrote true in QFT in general or only in pertubative QFT ? I have some idea of what is a "virtual" particle in QFT. But, when it is no more pertubative, I do not understand. |
| Mar14-08, 07:52 AM | #14 |
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| Mar18-08, 12:36 PM | #15 |
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marlon |
| Mar19-08, 01:35 AM | #16 |
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marlon, do you agree that particles are excitations, corresponding to some Fourier modes, of fields?
Here you explain so Are all particles excitation states, or are they not? |
| Mar19-08, 02:44 AM | #17 |
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this was a mistake in writing. I was only meaning that "I have some idea of what is a "virtual" particle in perturbative QFT" and only in perturbative QFT because I think this is an artefact of perturbative approximation of quantum mecanics. But, if you can proove the contrary, I will be eager for an explanation as my current understanding might be wrong. |
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