## Question about simplifying this equation...

tan x/sin x + 1/cos x

The choices are A. 2tan^2x B. 2cosx C. 2cosx-1 D. 2secx

Do I make the tan sin/cos and multiply by reciprocal of sin? I did that and end up with 1/cos + 1/cos

Recognitions:
 Quote by iBankingFTW tan x/sin x + 1/cos x The choices are A. 2tan^2x B. 2cosx C. 2cosx-1 D. 2secx Do I make the tan sin/cos and multiply by reciprocal of sin? I did that and end up with 1/cos + 1/cos
You got it right so far. Do you know what secx is?
 Tan x / Sin x + 1 /cos x Since tanx = (sinx/cosx) we can substitute and get: (Sinx / cos x)/ Sin x + 1 / cos x here we can cancel out the sin x 's and get 1 / cos x + 1 / cos x since the denominators are the same we can add and get 2 / cos x Now since sec x = 1 / cosx we get 2 sec x Make sense?

## Question about simplifying this equation...

 Quote by Diffy Tan x / Sin x + 1 /cos x Since tanx = (sinx/cosx) we can substitute and get: (Sinx / cos x)/ Sin x + 1 / cos x here we can cancel out the sin x 's and get 1 / cos x + 1 / cos x since the denominators are the same we can add and get 2 / cos x Now since sec x = 1 / cosx we get 2 sec x Make sense?
Yeah, thanks for that. But I thought about what mathman said and the answer was obvious, lol. Thanks a lot though for working it out.

 Quote by mathman You got it right so far. Do you know what secx is?
Yeah, so the 2(1/cosx) becomes 2secx...

That was pretty stupid, lol. Thanks though. This is a little off-topic for this thread but I really lack in courses like physics and math and I really like this forum (I'm new, lol) and what I like is how you guys don't just give an answer. You either show all the steps like Diffy did or what you did and made me think about it. :)
 I have another question I can't understand. Which expression is equivalent to cos(pi + theta) (I don't know how to import the signs. and I checked the computer's character map) So what I did was take cos(pi + theta) and put down the formula: cos pi * cos theta - sin pi * sin theta But I don't know what to do from there. I tried to see if I could do anything putting sin over cos but they're on opposite sides of the "-". Choices are: A. -cos theta B. cos theta C. -sin theta D. sin theta
 you have cos(pi) and Sin(pi) in your expressions... What is the cos(pi)? sin(pi)?
 Oh and for learning how to import the symbols, you can use Latex tags, there is a guide on this site somewhere, $$\pi\theta$$ Edit: Here is the link to the Latex tutorial: http://www.physicsforums.com/showthread.php?t=8997

 Quote by Diffy you have cos(pi) and Sin(pi) in your expressions... What is the cos(pi)? sin(pi)?
Thanks for telling me about the symbols. That should come in handy :)

Just realized this isn't the forum for homework questions so I'm going to make a new thread in the correct section.