
#1
Jun908, 11:57 PM

P: 160

1. The problem statement, all variables and given/known data
two infinite sheets of charge (one positive, one negative) are arranged parallel to each other and separated by a distance of 2m. a charge of 3 microcoulombs is realeased at the positive plate. when it reaches the negative plate it has a kinetic energy of 0.6 joules. what is the electric field between the plates 2. Relevant equations electric field of charge sheet E = sigma/2(epsilon_o) where sigma = charge density, epsilon_o = constant 8.85*10^12 energy U = 1/2 CV^2 where C is capacitance, v is electric potential C = Q/V where Q is charge, V is electric potential 3. The attempt at a solution do i assume sigma as constant? do i assume both sheets have the same electric field, so electric field between the sheets is the sum of the two? how does the energy play a role in determining the electric field, the equation for electric field is already specified, and can be solved in terms of constants, assuming sigma is constant too. if i use the energy and capacitance equation i get: U = 1/2[(Q/V)(V^2)] 0.6 = QV/2 i am not sure how Q, V relate to electric field, i'm lost actually... help appreciated 



#2
Jun1008, 12:18 AM

Sci Advisor
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P: 25,175

Yes, yes. Constant sigma. Constant E field. Now start throwing out equations you don't need. Don't stop too soon. You only need one.




#3
Jun1008, 07:30 AM

P: 160

still somewhat lost, i did find in actuality that using :
U = 1/2[(Q/V)(V^2)] 0.6 = QV/2 V = 400000 volts when Q = +3*10^6 coulombs but how does V relate to electric field E? 



#4
Jun1008, 09:25 AM

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P: 25,175

guassian infinite sheet and charge with kinetic energy 


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