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roots of unity |
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| Jul21-08, 07:58 AM | #1 |
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roots of unity
1. The problem statement, all variables and given/known data
if w is the nth root of unity, i.e. w= exp(2pi/n i) show: [latex](1-w)(1-w^2)...(1-w^{n-1})=n[/latex] 2. Relevant equations 3. The attempt at a solution since w^(n-a)= complex congugate of w^a terms on the left hand side are going to pair up to give [latex]|1-w|^2 |1-w^2|^2...[/latex] but I'm not sure what to do from here. Thanks |
| Jul21-08, 10:20 AM | #2 |
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I wouldn't do it that way at all!
It should be sufficient to note that the n roots of xn- 1= 0 are 1, w, w2, ..., wn-1 and so xn-1= (x-1)(x-w)(x-w2)...(x- wn-1). Dividing both sides by x- 1 we get (x-w)(x-w2)...(x- wn-1) on the right and what on the left? Now set x= 1. |
| Jul21-08, 10:49 AM | #3 |
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thanks
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