
#1
Sep3008, 10:19 PM

P: 22

1. The problem statement, all variables and given/known data
Find a value of the constant k such that the limit exists. 2. Relevant equations lim x to infinity of x^36/x^k+3 3. The attempt at a solution I started by setting the equation equal to infinity and attempted to rearrange it but got pretty much nowhere. I also broke it up using limit rules and also ended up nowhere. 



#2
Sep3008, 10:32 PM

Sci Advisor
HW Helper
Thanks
P: 25,161

Can you guess what a k might be? For the limit to exist the numerator and denominator have to grow at similar rates as x>infinity.




#3
Oct108, 03:38 PM

P: 22

So would k be 3? I'm not sure I'm understanding..




#4
Oct108, 03:42 PM

Sci Advisor
HW Helper
Thanks
P: 25,161

Find a value of constant "k" so a limit to infinity exists
Yes, k=3 is one value that works. What's the limit in that case? Can you show if k>3 the limit is 0 (so it exists) and if k<3 the limit is infinity (so it doesn't exist)? You were just asked to find 'a value'. There are lots of choices.




#5
Oct108, 03:46 PM

P: 22

oh my goodness. i just understood it now..thank you *bangs head on desk* :)




#6
Oct108, 04:42 PM

P: 22

so to show that say for k=4 the limit is 0, would I just divided each term top and bottom by x^4?




#7
Oct108, 04:48 PM

P: 22

and for k=3 the value of the limit would be 1, correct?




#8
Oct108, 05:14 PM

Sci Advisor
HW Helper
Thanks
P: 25,161




Register to reply 
Related Discussions  
Propositional Logic  "There Exists" dual  Calculus & Beyond Homework  0  
Mathematical Logic: "For all" and "There exists"  Math & Science Software  2  
Find values for which the limit exists...  Calculus & Beyond Homework  4  
a definitions for the terms "the limit does not exists"  Calculus  2 