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Calculating Final Temperature

by grapejellypie
Tags: calorimetry, heat capacity, thermochemistry
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grapejellypie
#1
Oct5-08, 07:10 PM
P: 14
1. The problem statement, all variables and given/known data
A 505g piece of copper tubing is heated to 99.9 degrees C and placed in an insulated vessel containing 59.8g of water at 24.8 degrees C. Assuming no loss of water and a heat capacity for the vessel of 10.0 J/K, what is the final temperature of the system? (c of coppuer is 0.387 J/(gk))


2. Relevant equations

q = c x mass x change in temperature
change in termperature = T[final] - T[initial]

3. The attempt at a solution
I have no idea how to go about solving this problem
1. The problem statement, all variables and given/known data



2. Relevant equations



3. The attempt at a solution
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Borek
#2
Oct6-08, 02:16 AM
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Heat lost = heat gained.
grapejellypie
#3
Oct6-08, 02:43 AM
P: 14
how do you account for the two separate systems combining into one?
(i.e. how would you deal with the two different masses?)

Borek
#4
Oct6-08, 02:58 AM
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Calculating Final Temperature

Treat heat gained/lost separately. Use equation you have already posted for each mass separately. The only commong thing in both equations will be the final temperature, and that's what you will solve for.
grapejellypie
#5
Oct6-08, 03:00 AM
P: 14
how do you incorporate the heat capacity of the vessel?
Borek
#6
Oct6-08, 03:38 AM
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Combine it with water (simply add them, nothing more fancy). It coul be given as vessel mass and specific heat, but the heat capacity is the same, just details are hidden - which completely doesn't matter.


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