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2-band, 3-band, 6-band Hamiltonian |
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| Feb18-09, 08:45 AM | #1 |
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2-band, 3-band, 6-band Hamiltonian
Can anybody tell me what they mean by 2, 3, 6 or any band hamiltonians. What does it even mean?
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| Feb18-09, 05:37 PM | #2 |
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The numbers refer to the number of electronic bands in a solid, 2 bands usually means just the conduction band, 4 bands the valence bands (light and heavy hole), 6 bands can mean either the valence bands (light, heavy and spin-orbit) or the conduction bands with the light and heavy hole bands.
For example, silicon and germanium can be modeled with 6 bands, GaAs needs 8. The more bands you use, the better the applroximation to a real solid you get. |
| Feb18-09, 11:26 PM | #3 |
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So for instance i have an excitonic state in piece of semiconductor. It occurs to me that the total wavefunction Y would be the product of the individual wavefunctions of the electron and the hole, or
Yexciton=yelectron*yhole and (lets say the semiconductor is a nanorod) in cylindrical coordinates yelectron=F(relectron,phi,z) yhole=F(rhole,phi,z)*Gmj*u where Gmj is the angular momentum coupling part and u are the Wannier functions. Assuming this is a correct initial rough approximation, how many bands are we talking about here? Does my question even make any sense? I'd really appreciate your help. |
| Feb19-09, 03:47 AM | #4 |
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2-band, 3-band, 6-band Hamiltonian
I'm fairly sure you can't calculate band gaps with a single electron-hole exchange; bands in solids like semiconductors are a function of long-range order; you have to derive the geometry, the minimal lattice and its shape and modes; there's materials science, molecular bonding in solids, electronics/solid-state, there's a lot that you can look into.
But it's a function of iterated small-scale order to long-range effects. |
| Feb19-09, 07:24 AM | #5 |
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ok i guess i didnt give enough detail. The exciton is a Wannier-Mott exciton with Bohr radius much larger than the lattice constant. The geometry is considered within the boundary conditions of the electron wavefunction, such that for a cylinder of length L~300Amstrong we have
y=AnlJl(bnlr)exp(-i*l*phy)*Sin(kz) where Anl is the normalization constant, Jl(bnlr) is the l thorder bessel function and bnl is the n-th zero to the l-th bessel function. All I am asking is how many bands we have here if the hole has the same form and also includes the 3j Wiegner symbol (angular momentum coupling) and Wannier periodic functions. |
| Feb19-09, 07:55 AM | #6 |
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You lost me here:
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| Feb19-09, 10:03 AM | #7 |
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| Feb19-09, 11:30 AM | #8 |
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| Feb19-09, 02:24 PM | #9 |
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| Feb20-09, 09:14 AM | #10 |
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What exactly is it you want to achieve? That is not particularly clear. What are you trying to calculate?
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| Feb20-09, 03:34 PM | #11 |
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| band, condensed matter, hamiltonian, nanoparticle, quantum |
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