
#1
Nov209, 02:34 PM

P: 262

Please help required with this integral:
(x/(xa))^0.5 where "a" is a start distance of 10^3 and the final distance needs to be 10^2 It looks simple but its not. Wolfram integrator gave this answer: Integrate[(x/(x  a))^0.5, x] == (0.*(x/(a + x))^0.5*(a + x)^0.5)/x^0.5 + (2.*(x/(a + x))^0.5*(a + x)^0.5*(1.*a + x)^0.5* Hypergeometric2F1[0.5, 0.5, 1.5, 1.  (1.*x)/a])/ (0. + x/a)^0.5 Which is way way over my head. Is there a simpler solution? 



#2
Nov309, 02:09 AM

HW Helper
P: 3,353

Assuming the integral you want to solve is [tex]\int \sqrt{ \frac{x}{xa}} dx[/tex], make the substitution [itex] x= a \sec^2 \theta[/itex].




#3
Nov309, 06:47 AM

P: 608





#4
Nov309, 07:20 AM

P: 262

difficult integral 


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