Problem with energy conservation

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Homework Help Overview

The discussion revolves around a physics problem related to energy conservation in the context of a teleski system. Participants are tasked with calculating the power required for the engine to maintain a constant speed while overcoming friction and gravitational forces as skiers ascend a slope.

Discussion Character

  • Exploratory, Conceptual clarification, Mathematical reasoning

Approaches and Questions Raised

  • The original poster attempts to apply energy conservation principles, incorporating mechanical, thermal, and chemical energy changes. Some participants question the correctness of the provided answer and the assumptions made regarding the frictional force and angle. Others suggest alternative methods, such as focusing on potential energy changes.

Discussion Status

The discussion is active, with multiple participants sharing their calculations and questioning the validity of the original answer. There is no explicit consensus on the correct power value, and various interpretations of the problem setup are being explored.

Contextual Notes

Participants are considering the effects of kinetic friction and the angle of the slope, with some noting potential discrepancies in the application of these factors. The original answer provided is significantly higher than the values calculated by others, leading to further inquiry into the assumptions and methods used.

diegojco
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Suppose you have a teleski to climb a skiway of d=600m and θ=15º respect horizontal and μk=0.06 is kinetic friction coefficient in the cable. 80 skiers of 75kg (m=6000kg in total) each one wants to climb at the top at v=2.5m/s constant, What's the power that engine must provide in order to maintain this speed with that charge of skiers? Answer: 350KW

I have used: Wexternal forces=ΔEmechanic+ΔEthermic+ΔEchemical=0, where ΔEmechanic=(m*(vf)2/2)+m*g*(hf)-(m*(vo)2/2)-m*g*(ho)=m*g*(hf), since vf=vo y ho=0, and ΔEthermic=fk*d=μk*m*g*d*cos(θ), and ΔEchemical is engine's energy to get the power, then:

P=-dEchemical/dt

and -dEchemical/dt=dEmechanic/dt+dEthermic/dt, hence:

P=m*g*v*(sin(θ)+μk*cos(θ))

P=46.61KW

This is not the answer, why?, please guide me and tell me what's the mistake.
 
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I'm getting something around 41kW as well. Keep in mind that the frictional force is directed against the motion of the gondola (teleski) up the cable, meaning the value of theta when multiplying by cos(theta) for friction is 0. The answer may be wrong; I don't know how they got an answer nine times larger than mine...
 
I'm getting 46 kW too. The answer of 350 kW must be wrong.
 
diego, as far as method goes, I'm not sure what you did (probably ok since your answer looks right), but I usually approach this kind of problem using potential energy concepts. I set the time as one second, then find the vertical distance traveled given the speed provided, plug that into find the change in gravitational potential energy, and can therefore find power (you get J/s, which is Watts). Factor in non-conservative forces and angles when required. Just my method.
 

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