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Are Noether charges a rep of the generators on the Hilbert space 
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#1
Feb1111, 05:04 AM

P: 25

I'm trying to understand the relationship between conserved charges and how operators transform. I know that we can find conserved charges from Noether's theorem. If (for internal symmetries) I call them [tex] Q^a = \int d^3x \frac{\partial L}{\partial \partial_0 \phi_i} \Delta \phi_i^a [/tex] then is it always the case that operators transform like
[tex] \hat O \rightarrow e^{i t_a Q^a} \hat O e^{i t_a Q^a} [/tex] i.e. are the conserved charges the rep of the generators on the Hilbert space? Thanks for any help! 


#2
Feb1111, 03:22 PM

Sci Advisor
P: 908

Yes, they do generate the correct transformation on the fields AND satisfy the Lie algebra of the symmetry group. More importantly, they ( in the internal case) DON’T need to be CONSERVED to do the job.
sam 


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