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Dimensionless equations |
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| Mar4-11, 06:05 AM | #1 |
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Dimensionless equations
I have a problem that might sound simple, but has been bugging me for months. In a physical equation, the units are regarded as multipliers - so to take a very simple example in SI:
1) F[N]=M[kg]a[m/s2] And, of course, [N] is equivalent to [kg][m/s2], so all is well. Here's my problem: lets say I want to adjust the equation, so that my mass measurements are in grams [g] rather than [kg]. Direct substitution for 1kg = 1000g into equation 1) gives: 2) F(N)=1000M[g]a[m/s2] Which is clearly incorrect. (a mass of 1g accelerated at 1 m/s2 would compute a force of 1000N - wrong - The equation actually needs to be divided by 1000 on the RHS.) The logic looks perfect - but the result is wrong. The problem is resolved in *all* equations by regarding the algebraic symbols to be *divided* by the unit - so why do we consider them to be multiplied???? What's my problem!!!!??? |
| Mar4-11, 07:44 AM | #2 |
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Recognitions:
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Hi puzzler. Numerically the mass in kg is 1/1000-th of the mass in grams.
So the correct substitution is F[N] = M[grams]/1000 a[m/s^2] |
| Mar4-11, 07:54 AM | #3 |
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Do you see the problem? In this verbal equation, *in* must stand for divide by - not multiply. If we apply the rule that *in* stands for divide, the verbal equation now works: M/kg = (1/000) M/g This is consistent. But it brings us back to the original point - numbers in physical equations are divided by their units - not multiplied. Maybe it looks like this: M(kg)/[kg] The parentheses give the expected unit: the brackets the divisor. This makes the whole equation dimensionless. Now I can substitute [1kg] = [1000g], and everything will work as expected. Can anyone expand - it's a worry!! (here's a thought: M of kg = 1000 x M of g. But M in Kg = (1/000) M in g. Note the difference between 'of' multiply, and 'in' divide'. I've been doing physics for 20 years - and I'm suddenly puzzled!!) |
| Mar4-11, 10:28 AM | #4 |
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Dimensionless equations
I think I've solved my own problem: but I would appreciate all comments and criticism:
It seems that, maybe, all physical equations must, ultimately, be numerical, and therefore - ultimately dimensionless. I suggest my mistake is in thinking that the M, in F=Ma, is fixed - as the unit quantities move around it. (note that: F=Ma is just a simple example - the rules are expected to apply to all equations) Heres a solution: If M is not fixed, we can have M1, M2 - two versions: if M1(kg) = M2(g) Now we can write: 1000M1(g) = M2(g) Hence M1=M2/1000 If we substitute this into the equation we get the desired result (see above) The conclusion *must be* that all physical equations - even if they appear to have units - are ultimately dimensionless. We make them dimensionless by correct choice of units. If we change those units - we must allow the dimensionless equation to adapt to the units (not vice versa) Ultimately, even in physical equations, numbers = numbers. Please feel free to argue and discuss. |
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