|Mar4-11, 06:05 AM||#1|
I have a problem that might sound simple, but has been bugging me for months. In a physical equation, the units are regarded as multipliers - so to take a very simple example in SI:
And, of course, [N] is equivalent to [kg][m/s2], so all is well.
Here's my problem: lets say I want to adjust the equation, so that my mass measurements are in grams [g] rather than [kg].
Direct substitution for 1kg = 1000g into equation 1) gives:
Which is clearly incorrect.
(a mass of 1g accelerated at 1 m/s2 would compute a force of 1000N - wrong - The equation actually needs to be divided by 1000 on the RHS.)
The logic looks perfect - but the result is wrong.
The problem is resolved in *all* equations by regarding the algebraic symbols to be *divided* by the unit - so why do we consider them to be multiplied????
What's my problem!!!!???
|Mar4-11, 07:44 AM||#2|
Hi puzzler. Numerically the mass in kg is 1/1000-th of the mass in grams.
So the correct substitution is F[N] = M[grams]/1000 a[m/s^2]
|Mar4-11, 07:54 AM||#3|
Do you see the problem? In this verbal equation, *in* must stand for divide by - not multiply.
If we apply the rule that *in* stands for divide, the verbal equation now works:
M/kg = (1/000) M/g
This is consistent. But it brings us back to the original point - numbers in physical equations are divided by their units - not multiplied.
Maybe it looks like this: M(kg)/[kg]
The parentheses give the expected unit: the brackets the divisor. This makes the whole equation dimensionless.
Now I can substitute [1kg] = [1000g], and everything will work as expected.
Can anyone expand - it's a worry!!
(here's a thought: M of kg = 1000 x M of g. But M in Kg = (1/000) M in g. Note the difference between 'of' multiply, and 'in' divide'. I've been doing physics for 20 years - and I'm suddenly puzzled!!)
|Mar4-11, 10:28 AM||#4|
I think I've solved my own problem: but I would appreciate all comments and criticism:
It seems that, maybe, all physical equations must, ultimately, be numerical, and therefore - ultimately dimensionless.
I suggest my mistake is in thinking that the M, in F=Ma, is fixed - as the unit quantities move around it.
(note that: F=Ma is just a simple example - the rules are expected to apply to all equations)
Heres a solution: If M is not fixed, we can have M1, M2 - two versions:
if M1(kg) = M2(g)
Now we can write:
1000M1(g) = M2(g)
If we substitute this into the equation we get the desired result (see above)
The conclusion *must be* that all physical equations - even if they appear to have units - are ultimately dimensionless.
We make them dimensionless by correct choice of units.
If we change those units - we must allow the dimensionless equation to adapt to the units (not vice versa)
Ultimately, even in physical equations, numbers = numbers.
Please feel free to argue and discuss.
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