How many revolutions does a diver make while falling from a cliff?

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Homework Help Overview

The problem involves a diver running off a cliff that is 8.6 meters high and rotating while falling. The diver has an average angular speed of 1.4 revolutions per second. Participants are exploring how to calculate the number of revolutions made during the fall, considering the height of the cliff and the rotational motion involved.

Discussion Character

  • Exploratory, Assumption checking, Problem interpretation

Approaches and Questions Raised

  • Participants discuss the need to find the time it takes to fall 8.6 meters and whether the rotational motion affects this time. There are questions about using kinematic equations and how to relate linear distance to angular motion.

Discussion Status

Some participants have provided guidance on using average angular speed as a constant and suggested methods for calculating the time of fall. There is an ongoing exploration of the calculations involved, with varying interpretations of the results and methods used.

Contextual Notes

Participants express confusion regarding the application of kinematic equations in the context of rotational motion and the specific examples provided in their learning materials. There is a noted lack of clear examples in the original poster's resources, contributing to the uncertainty in solving the problem.

BlackMamba
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Hello,

I have a problem where I honestly have no idea how to get started. I have a slight idea what might be invloved but other than that, I am stumped.

Here's the problem: At the local swimming hole, a favorite trick is to run horizontally off a cliff that is 8.6m above the water. One diver runs off the edge of the cliff, tucks into a "ball," and rotates on the way down with an average angular speed of 1.4 rev/s. Ignore air resistance and determine the number of revolutions she makes while on the way down.

What's throwing me is that there is a height involved and none of the examples provided in my book or from my professor for that matter included a problem with height. I think I read somewhere however that d = s but again, I don't understand how to work this. I know I will have to use one of the Rotational Kinematic equations, but like I said this is about all I know.

Thanks for any help provided.
 
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1. Find the time it takes to fall 8.6 meters.
The fact that you are rotating, will not affect that time.
2. You may now determine the number of cycles the diver has made.
 
Ok, So what I know is:

Theta: -
Omega initial: 1.4 rev/s
Omega final: -
alpha: -
time: ?

Again I'm still stuck on the distance portion of that. Do I use one of the regular kinematic equations to find time or do I have to convert the 8.6m to something else to use one of the rotational kinematic equations?
 
You've been given the AVERAGE angular speed. Use that as a constant...
"Do I use one of the regular kinematic equations to find time"
Yes!
Setting your water surface at y=0, you have vertical position at time "t":
[tex]y(t)=8.6-\frac{gt^{2}}{2}[/tex]
Find the "t"-value T so that y(T)=0
 
Hmm, I don't think I did this correctly. My answer is 1.32.
 
1.32 what? seconds or revolutions??
 
Oh seconds. Sorry about that.
 
Seems about right..
 
Oh, ok. Well, I finished out the problem the way I thought I should and have come to get an answer of 11.93. Does that sound right? I'm thinking that 11 revolutions is a bit much in 8 meters.
 
  • #10
However did you manage that?
1.4(rev/s)*1.32s=11.93(revs)?
 
  • #11
I used what I thought I was supposed to do. LOL I used a kinematic equation. Obviously that was not the right thing to do. I am a complete novice when it comes to physics. If my book doesn't have clear and explicit examples to follow, then I am sunk when it comes to doing a problem.

Anyway, the correct answer would be 1.85 revolutions.

Thank you for your help. It is much appreciated. :smile:
 

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