Potential and Kinetic energy and a sled

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Homework Help Overview

The discussion revolves around a physics problem involving potential and kinetic energy related to a sled and rider at the top of a hill. The problem includes calculations of potential energy, total mechanical energy, and kinetic energy at different points in the scenario.

Discussion Character

  • Exploratory, Conceptual clarification, Mathematical reasoning

Approaches and Questions Raised

  • The original poster attempts to calculate potential energy using the formula PE=mgh and questions the total mechanical energy after an initial push. Some participants suggest verifying energy conservation principles and consider the relationship between initial and final energy states.

Discussion Status

Participants are exploring the calculations and relationships between potential energy, kinetic energy, and total mechanical energy. There is an ongoing discussion about the correct application of formulas and the implications of energy conservation, with no explicit consensus reached yet.

Contextual Notes

Assumptions include ignoring friction and considering a reference level at the bottom of the hill. There is also uncertainty regarding the correct interpretation of kinetic energy versus total energy in the context of the problem.

Red04Cobra
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A sled and rider with a combined mass of 50kg are at the top of a hill that is 15m above the level ground. The sled is given a push providing an initial kinetic energy at the top of the hill of 1600J.

A: choosing a reference level at the bottom of the hill what is the potential energy of the sled and rider at the top of the hill?

B: After the push what is the total mechanical energy of the sled and rider at the top of the hill?

C: If friction is ignored what will be the kinetic energy of the sled and rider at the bottom of the hill?


So far I have this..and I'm not sure if it's right.

PE=mgh PE= (50kg)*(9.8m/sec squared)*(15m) = 7350J
E=PE+KE 1600J+7350J = 8950J

after that I'm not really sure. Any help is greatly appreciated!
 
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You know the total energy, and if no work is done (draw a free body diagram if you want to verify this)...then the energy in the beginning is equal to the energy at the end...

You know the potential energy at the end (h = 0)...so all you have is one unknown (the velocity).
 
So..if I take (2*KE)/m and take the square root that would be right?
 
well, not KE (assuming you mean Kinetic Energy), but Total Energy...

(2*Total Energy) \ m and take the square root
 

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