What is the speed of the space shuttle when a ball is dropped?

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Homework Help Overview

The problem involves a space shuttle reaching an altitude of 100 meters and the subsequent dropping of a ball. Participants are exploring the relationship between the shuttle's speed at the moment the ball is dropped and the motion of the ball as it falls to the ground.

Discussion Character

  • Exploratory, Assumption checking, Conceptual clarification

Approaches and Questions Raised

  • Participants discuss the assumption of uniform acceleration for the shuttle and the implications for the ball's motion. There are attempts to analyze the motion of the ball in relation to the shuttle's speed at the moment of release.

Discussion Status

Some participants are questioning the validity of the assumptions made regarding the shuttle's acceleration. Others are exploring the dynamics of the ball's motion after being dropped, with varying levels of understanding and clarity. A few participants express frustration and seek additional guidance.

Contextual Notes

There is a mention of the need for more information regarding the distance the ball travels to reach its maximum height, indicating potential gaps in the problem setup. The discussion reflects uncertainty about the assumptions made regarding the shuttle's motion.

UrbanXrisis
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A space shuttle is launched from the earth. It reaches an altitude of 100 meters in 6.1 seconds. At 6.1 seconds, a ball is dropped and hits the ground in 8.5 seconds. What is the speed of the space shuttle when the ball is dropped?

I am really stumped by this one

d=0.5at^2
100=(0.5)a (6.1s)^2
a=5.37m/s^2

Vf=vi+at
v=(5.37m/s^2) * 6.1s
v=32.757m/s?
 
Last edited:
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keep your eye on the ball

UrbanXrisis said:
I am really stumped by this one

d=0.5at^2
100=(0.5)a (6.1s)^2
a=5.37m/s^2
This assumes that the shuttle uniformly accelerates. Instead, analyze the motion of the falling ball, since the ball and shuttle have the same speed when the ball is dropped.
 
I've looked at this problem in many different ways already. Trust me, I need more clues. I've tired all posibilities
 
the ball has upward velocity same as the space shuttle the moment it is dropped. the ball falls under the effect of gravity. your assumption about the rocket which moves with constant acceleration is not valid as doc al said. keep your eye on the ball, not the rocket. i got 30 m/s.
 
Last edited:
could you explain what you mean by "keep the eye on the ball"?
 
The ball goes up then once it is released, it will still go up but with decreasing velocity. Then, it will start to fall and pass the same point it was released with equal velocity as when it was released. It then accelerates downwards and hits the floor...I don't see any equation or way in solving this. I need to know the distance it travled to reach its max point...or some kind of clue
 
nevermind, I got it...I thought it would be more complex...
 

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