## Projectile Motion: Horizontal distance

1. The problem statement, all variables and given/known data
A jet flying at 250m/s at an angle of 20 degrees above the horizontal releases a bomb 200m above the ground, how far does the bomb travel horizontally before hitting the ground?

2. Relevant equations
vix = vicosthetha
viy= visinthetha
not sure what else...

3. The attempt at a solution
vix= 234.923ms
viy= 85.505 ms

This is all I've managed to figure out so far, does anyone know more relevant equations that may help me out?

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 okay so you have got the component velocities which is always a good start. next step is to recognise the equations you will need. try y=yi+viyt+(at2)/2 and R(range)=vxt from these u must realise the variables you are given, what you want(range) and the variables you need to find okay in reread your question and saw that you specifically asked for an equation. you should know that the equations i gave above can be derived from the equation for constant acceleration( in this case constant gravity). this equation is x=xi+vit+at2/2 where x is th final DISPLACEMENT, xi is initial displacement tis time and a is the CONSTANT acceleration. this formula does not work with variable acceleration