Work Done on Charge +q at Distance D from Semi-Infinite Grounded Metal

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SUMMARY

The work done in bringing a charge +q from infinity to a distance D from a semi-infinite grounded metal surface is calculated using the formula F = [-1/(4πe0)](q*-q)/(2d²). The integration of this force from the limits x = d to x = infinity yields the total work done. The term (2d²) in the denominator arises from the method of image charges, where the grounded metal induces a charge -q, creating an effective interaction distance that influences the force calculation.

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Homework Statement



The work done in bringing a charge +q from infinity in free space to a postion at a distance D in front of a semi-infinite grounded metal surface?

The Attempt at a Solution


Actually i know the method to solve it, but didn't understand its logic.
F=[-1/(4pi*e0)](q*-q)/(2d*d)
When we integrate this F as integral of F.dr between the limits x= d and x= infinity we get the result.
my question is what is this semi infinite grounded metal? how does this (2d*d) appear in the denominator? des this q and -q appears because of induction charging ?
 
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Isn't this the http://en.wikipedia.org/wiki/Method_of_image_charges" ?

Dont' know what's meant by a "semi-infinite" grounded metal though.

Maybe it's metal taking up half of all available space, and having a plane surface, like http://upload.wikimedia.org/wikipedia/commons/4/4c/Method_of_mirror_images.png" . In that case, yeah the -q would be the induced charge. But it looks to me like it would be ((2x)*(2x)) instead of (2d*d) in the denominator, where x is the variable distance of the charge +q from the surface as it moves.
 
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