Damped Simple Harmonic oscillator

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SUMMARY

A damped simple harmonic oscillator with mass m = 260 g, spring constant k = 95 N/m, and damping coefficient b = 75 g/s has an amplitude ratio of damped oscillations to initial amplitude at the end of 20 cycles calculated as Adamped / Ainitial = e^(-bt/2m). By determining the period T = 2π√(m/k), which equals 0.12 s, and substituting t = 20T into the amplitude ratio equation, the result is approximately 0.491. This indicates that the amplitude decreases to about half its initial value after 20 cycles.

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a damped simple harmonic oscillator has mass m = 260 g, k = 95 N/m, and b = 75 g/s. Assume all other components have negligible mass. What is the ratio of the amplitude of the damped oscillations to the initial amplitude at the end of 20 cycles (Adamped / Ainitial)?

having trouble getting started, any help?

I know the equations, just not how to use them :frown:
 
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Calculate the time taken for 20 cycles from the equation for frequency that you have. (Reciprocal of frequency is the time taken for one oscillation.)

Then, calculate the amplitude after that time from the expression for amplitude.
Now just take the ratio.


Spacetime
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No problem, let's break it down step by step. First, we need to understand what a damped simple harmonic oscillator is. It is a system where a mass is attached to a spring and is subject to a damping force, which is a force that opposes the motion of the mass. This results in the amplitude of the oscillations decreasing over time.

Now, to solve for the ratio of the amplitude of the damped oscillations to the initial amplitude at the end of 20 cycles, we can use the equation:

Adamped / Ainitial = e^(-bt/2m)

In this equation, e is the base of the natural logarithm, b is the damping coefficient, t is the time, and m is the mass.

We are given the values for m, k, and b, so we just need to plug them into the equation. Since we are looking at the end of 20 cycles, we can assume that t = 20T, where T is the period of the oscillations.

To find the period, we can use the equation T = 2π√(m/k). Plugging in the values, we get T = 0.12 s.

Now, we can plug in all the values into the original equation:

Adamped / Ainitial = e^(-bt/2m)

= e^(-0.075*20*0.12/2*0.26)

= 0.491

Therefore, the ratio of the amplitude of the damped oscillations to the initial amplitude at the end of 20 cycles is approximately 0.491. This means that the amplitude of the oscillations will decrease by about half after 20 cycles.

I hope this helps you understand how to approach and solve problems involving damped simple harmonic oscillators. Remember to always start by understanding the concept and then plugging in the given values into the appropriate equations. Good luck!
 

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