Solving a 20% Efficient Real Engine Problem

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The discussion centers on a homework problem involving a 20% efficient real engine and an ideal Carnot engine. The real engine accelerates a train to 5.00 m/s, while the Carnot engine achieves 6.50 m/s using the same amount of fuel. It is established that the Carnot engine produces 1.69 times more kinetic energy than the real engine, leading to the conclusion that the efficiency of the ideal engine is 1.69 times that of the real engine. The efficiency formula for the Carnot cycle, Efficiency = (T_H - T_C) / T_H, is utilized to derive the temperature of the steam at the hot reservoir.

PREREQUISITES
  • Understanding of thermodynamic efficiency concepts
  • Familiarity with the Carnot engine principles
  • Knowledge of kinetic energy calculations
  • Basic grasp of temperature scales, particularly Kelvin
NEXT STEPS
  • Study the Carnot efficiency formula in detail
  • Explore kinetic energy equations and their applications in thermodynamics
  • Learn about real vs. ideal engine performance comparisons
  • Investigate the properties of steam and its temperature relations in thermodynamic cycles
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Students studying thermodynamics, physics educators, and engineers interested in engine efficiency and performance optimization.

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Homework question:

A 20% efficient real engine is used to speed up a train from rest to 5.00m/s. It is known that an ideal (Carnot) engine having the same cold and hot reservoirs would accelerate the same train from rest to 6.50m/s using the same amount of fuel. Assuming that the engines use air at 27C as a cold reservoir, find the temperature of steam at the hot reservoir.

I think what my real problem is is that I'm not sure what the fact that they use the same amount of fuel is telling me. I know that something will be equal between them besides the cold reservoir, but I'm not sure what. The work can't be the same because the final speeds are different.

Can anyone help me to understand this please? Thanks
 
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jaidon said:
Homework question:

A 20% efficient real engine is used to speed up a train from rest to 5.00m/s. It is known that an ideal (Carnot) engine having the same cold and hot reservoirs would accelerate the same train from rest to 6.50m/s using the same amount of fuel. Assuming that the engines use air at 27C as a cold reservoir, find the temperature of steam at the hot reservoir.

I think what my real problem is is that I'm not sure what the fact that they use the same amount of fuel is telling me. I know that something will be equal between them besides the cold reservoir, but I'm not sure what. The work can't be the same because the final speeds are different.

Can anyone help me to understand this please? Thanks
Using the same amount of fuel to accelerate to 6.5 m/s tells you that the ideal Carnot engine would produce 1.69 times more kinetic energy from the same amount of fuel as the real engine does. So it is 1.69 times more efficient.

Since for the Carnot cycle, the efficiency is:
[tex]\frac{T_H - T_C}{T_H}[/tex] (temperatures in Kelvins)
and we know that
Efficiencyideal = 1.69Efficiencyreal
you can work out [itex]T_H[/itex].

AM
 
jaidon said:
Homework question:

A 20% efficient real engine is used to speed up a train from rest to 5.00m/s. It is known that an ideal (Carnot) engine having the same cold and hot reservoirs would accelerate the same train from rest to 6.50m/s using the same amount of fuel. Assuming that the engines use air at 27C as a cold reservoir, find the temperature of steam at the hot reservoir.

I think what my real problem is is that I'm not sure what the fact that they use the same amount of fuel is telling me. I know that something will be equal between them besides the cold reservoir, but I'm not sure what. The work can't be the same because the final speeds are different.

Can anyone help me to understand this please? Thanks

The same problem and the same answer:
https://www.physicsforums.com/showthread.php?t=51671

I think both of you have used the same book.
 

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