Calculation of RMS Voltage and Current


by vinayakbhat82
Tags: power, rms current, rms voltage
vinayakbhat82
vinayakbhat82 is offline
#1
Nov18-11, 03:30 AM
P: 6
I've a theoretical circuit that resembles an on-off switch with a duty cycle of 50%. The voltage input to the circuit is a constant 5v. The current drawn from the source is 1A when switch is ON and 0A when OFF. What is the Vrms and Irms?

From what I know:
Vrms for constant 5v is 5v.
Irms for above current (square wave with 50% duty cycle) would be I/√2 = 1/√2.
This imples P=Vrms*Irms = 5/√2

However, if we separately do some calculations for power, it would be like 5*1*0.5 (V*I*duty chle) = 5/2.

Can this discrepancy be explained please? Please let me know what am I missing.
Phys.Org News Partner Physics news on Phys.org
Information storage for the next generation of plastic computers
Scientists capture ultrafast snapshots of light-driven superconductivity
Progress in the fight against quantum dissipation
willem2
willem2 is offline
#2
Nov18-11, 04:04 AM
P: 1,351
Quote Quote by vinayakbhat82 View Post
I've a theoretical circuit that resembles an on-off switch with a duty cycle of 50%. The voltage input to the circuit is a constant 5v. The current drawn from the source is 1A when switch is ON and 0A when OFF. What is the Vrms and Irms?

From what I know:
Vrms for constant 5v is 5v.
Prms = Vrms * Irms is only valid for a purely resistive load.

If you have a battery, a switch and a resistor in series, you can consider V and I across the resistor, and V won't be constant, so Vrms isn't 5V.

You can also consider V and I across the resistor and switch, and then Prms = Vrms * Irms
isn't valid and you have to do an integral of V(t)*I(t) over one cycle.
vinayakbhat82
vinayakbhat82 is offline
#3
Nov18-11, 05:27 AM
P: 6
Hey willem2,

Thanks for the reply.

Yes, I did have that idea earlier, but I was trying to answer the following: If I've a blackbox that has the circuit you mentioned i.e. switch and a resistor with no access to internal nodes and I need to have a DC equivalent of the original source that delivers the same power, how would I arrive at the numbers if I was provided with the voltage and current waveforms at the boundary. By reverse engineering, we may say that Vrms needs to be 5/√2 in this case, however, I wanted to understand the rationale behind doing so.

I completely agree to your point that the rms voltage across the resistor would not be 5v, but would rather be 5/√2.

Is there a term called Prms or is it just P/ If so, please help me understand. Also I believe, integrating V*I over time will give you Energy.

willem2
willem2 is offline
#4
Nov18-11, 06:24 AM
P: 1,351

Calculation of RMS Voltage and Current


Quote Quote by vinayakbhat82 View Post

Is there a term called Prms or is it just P/ If so, please help me understand. Also I believe, integrating V*I over time will give you Energy.
There's no Prms, just average power.

The integral indeed gives the energy used in one period, so you'll have to divide by the length of the period to get the average power.
256bits
256bits is offline
#5
Nov18-11, 01:43 PM
P: 1,258
Irms for above current (square wave with 50% duty cycle) would be I/√2 = 1/√2.
This is valid only for a sine wave. ie the I/√2


Register to reply

Related Discussions
Figuring out voltage across resistor and current in loop given initial voltage input Engineering, Comp Sci, & Technology Homework 2
Why is there a flatband voltage in the calculation of Threshold voltage? Introductory Physics Homework 0
voltage and current calculation on a mixed circuit Introductory Physics Homework 2
current to voltage conterter and voltage to current converter Engineering, Comp Sci, & Technology Homework 3