Scale Reading of Normal Force: Due by Midnight!


by IBdoomed
Tags: free body diagram, normal force, trigometry
IBdoomed
IBdoomed is offline
#1
Nov20-11, 09:37 PM
P: 16
Remember that a scale records the value of
the normal force, not a personís actual weight.
Draw a FBD. Rotate your coordinate system.

A 61 kg student weighs himself by standing
on a scale mounted on a skateboard that is
rolling down an incline, as shown. Assume
there is no friction so that the force exerted
by the incline on the skateboard is normal to
the incline.
The acceleration of gravity is 9.81 m/s

What is the reading on the scale if the angle
of the slope is 29◦?
Answer in units of N

I have my free body diagram with Fn going up and to the left and Fg gong straight down. I do not understand how to rotate the FBD or what that would accomplish...
ANY HELP WOULD BE MUCH APPRECIATED!!!
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PhanthomJay
PhanthomJay is offline
#2
Nov20-11, 10:03 PM
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Your FBD is correct. Now break up the weight force into components parallel and perpendicular to the plane, and cross out the initial weight vector. The sum of forces perpendicular to the incline must equal zero, since the skateboarder does not lift off the incline in that direction.
IBdoomed
IBdoomed is offline
#3
Nov20-11, 10:07 PM
P: 16
much thanks! mission accomplished


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