## Projectile launch at elevated height on angle

1. The problem statement, all variables and given/known data

a baseball player hits a home run. The ball's velocity as it leaves the bat is 45m/s at an angle of 36.9° above the horizontal. At the point of impact with the bat, the ball is 1 m above ground level, and as it clears the fence it is back down to 11 m above ground level. How far from home plate is the fence at this point?

2. Relevant equations
linear motion equations
basic sin and cos
v=d/t

3. The attempt at a solution

so I started with finding the Vv and the Vh velocties
vh= 45cos6.9= 36.0
Vv= 45sin36.9 = 27.0

Vv
v1: 27 m/s
v2:*27.4m/s
a: -9.8m/s
t:*5.5
d: -1m

and Vh
vave: 36m/s
t:*5.5
d:*198m

*I found the time using the quadratic formula and came up with 5.5 seconds
* I calculated the total distance the ball travelled using the formula d = v×t and got 198 m
* calulated the v2 for the Vv to be 27.4 m/s using linear motion equation
I'm thinking i need a colum for the fence distance now, however, this part is slightly iffy.

Vh for fence
vave:
t:T
d: 198-D

Vv for fence
v1:
v2:
a:-9.8m/s
t:T
d: -11m

At this point I've hit a dead end.
 PhysOrg.com science news on PhysOrg.com >> Ants and carnivorous plants conspire for mutualistic feeding>> Forecast for Titan: Wild weather could be ahead>> Researchers stitch defects into the world's thinnest semiconductor
 The question states the ball is at 11m above the ground So displacement is 10m. Calculate your time again.(its not right) After you have time You will need to multiply it by v(h)*t to get d.(as you already did) Thats all.thats your answer I dont understand what (and why)you are doing in the latter part of your post.
 Hmm, I always manage to overcomplicate an easy question. thanks, I calculated my time to be 5.1 secs.

## Projectile launch at elevated height on angle

 Quote by rahrahrah1 Hmm, I always manage to overcomplicate an easy question. thanks, I calculated my time to be 5.1 secs.

Always draw a diagram :-)
That shortens the problem in so many ways.