The question:Rewriting Series with Sigma Notation

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Homework Help Overview

The discussion revolves around expressing a series using sigma notation, specifically the series 1 - 2 + 4 - 8 + 16 - 32. Participants are examining different representations of this series and comparing their answers to a provided book solution.

Discussion Character

  • Exploratory, Assumption checking, Problem interpretation

Approaches and Questions Raised

  • Participants are attempting to express the series in sigma notation and are questioning the correctness of their representations. There is a focus on the signs of the terms and the implications of different formulations.

Discussion Status

Multiple interpretations of the sigma notation are being explored, with some participants providing corrections and clarifications regarding the signs and structure of the expressions. There is an acknowledgment of mistakes in the original poster's notation, but no consensus has been reached on the best representation.

Contextual Notes

Participants note discrepancies between their answers and the book's answer, leading to discussions about potential misinterpretations or typographical errors in the provided solutions.

Mo
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Series and "Sigma" Notation

I have been revising over the sigma/sequences and series chapters, this is the second question now where i have had different answers to the book - yet- my answers seem to work - i think...

The question :

Write in [tex]\sum[/tex] notation

1 - 2 + 4 - 8 + 16 - 32


My answer is:

[tex]\sum_{0}^5 -2^r[/tex]

Is this correct?

Thie answer in the book by the way is:

[tex]\sum_{1}^6 (-1)^{r+1} \ 2r^{r-1}[/tex]

Regards,
Mo
 
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Mo said:
I have been revising over the sigma/sequences and series chapters, this is the second question now where i have had different answers to the book - yet- my answers seem to work - i think...

The question :

Write in [tex]\sum[/tex] notation

1 - 2 + 4 - 8 + 16 - 32


My answer is:

[tex]\sum_{0}^5 -2^r[/tex]

Is this correct?
...

Nope. Every term in that sum is negative (which is not true for 1 - 2 + 4...).
 
Then the answer in the books seems wrong and yours as well.
[tex]1-2+4-8+16-32=(-)^{0}2^{0}+(-)^{1}2^{1}+(-)^{2}2^{2}+(-)^{3}2^{3}+(-)^{4}2^{4}+(-)^{5}2^{5}=\sum_{k=0}^{5}(-)^{k}2^{k}[/tex]

You might have mistyped the answer in the book.

Daniel.
 
Yes i have typed in ther answer from the book wrongly, very sorry about that.

[tex]\sum_{1}^6 (-1)^{r+1} \ 2^{r-1}[/tex]

is the correct one.

However i still can't see how my answer is wrong!

when r is 0 , the answer is +1
when r is 1 , the answer is -2
when r is 2 , the answer is +4
when r is 3 , the answer is -8

so this would mean +1-2+4-8 ? Or maybe I am making a really stupid mistake here!

Thanks for your replies so far!
 
Mo said:
However i still can't see how my answer is wrong!

when r is 0 , the answer is +1
when r is 1 , the answer is -2
when r is 2 , the answer is +4
when r is 3 , the answer is -8

so this would mean +1-2+4-8 ? Or maybe I am making a really stupid mistake here!

Thanks for your replies so far!

At first, I thought your answer was right. It's not, cos your sum is -2^r and not (-2)^r. When r is 0, for your answer, you get -1, ie. -1 x 2^0.
 
Your answer would have been correct if you would have used this one: -

The following code was used to generate this LaTeX image:



[tex]\sum_{k=0}^{5}(-2)^{k}[/tex]
 
Look at it this way: If you had

[tex]\sum (1-2^r)[/tex]

would you say that was

[tex](1-1) + (1-2) + (1-4) + ...[/tex]

or

[tex](1+1) + (1-2) + (1+4) + ...[/tex]

?

When you evaluate an expression that doesn't have parentheses inside of it, and is on a single line, exponents always come first, then multiplication/division, then addition/subtraction.
 
Thank you for your replies all

Offcourse i should have used brackets :sigh: next time ill remember!

thanks again

Regards,
Mo

PS: JTbell, this first one ..
 
I just realized that I got the signs backwards on my second choice.

Oh well, you got the right idea, anyway!
 

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