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Chemistry: How do I write an ionic equation for this reaction? |
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| Jun14-12, 04:08 PM | #1 |
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Chemistry: How do I write an ionic equation for this reaction?
1. The problem statement, all variables and given/known data
I was doing this problem for HW online, that asks to write the ionic equation for a reaction, but I'm completely stuck. After using all my attempts (i.e., I can no longer submit the answer even if it is right, ) I still couldn't get the right answer. We've only done very simple ionic equations in class, so I couldn't apply what we did in class to the problem. Anyway here is the reaction to make an ionic equation for:[tex]Ba(OH)_2 (aq) + H_{3}PO_{4} (aq) \rightarrow [/tex] 2. Relevant equations Not applicable. 3. The attempt at a solution Here is the last answer I attempted. Wolframalpha told me that the compound phosphoric acid (H3PO4) was "very soluable" so I separated it into ions. That was about all it was able to help me with. I assumed that the phosphate separated from the hydrogen atoms to combine with the barium and create an insoluable solid (according to my textbook, any non-alkali metal combined with phosphate is insoluable). So with all that, I thought the ionic equation would logically be: [tex]3H^{+}(aq) + 2{PO_4}^{-3}(aq) + 3Ba^{+2}(aq) + 2OH^{-}(aq) \rightarrow Ba_3(PO_4)_2(s) + 3H^{+}(aq) + 2OH^{-}(aq)[/tex] This is wrong as my fifth and final attempt told me . . . The super vague reason the system gives me for this being wrong is that "Your answer contains an ambiguous or incomplete reaction equation. Check all the components on the reactant-side of the equation. Check all the components on the product-side of the equation." If you need anymore information on my thought process or anything like that, please ask. Thanks in advance for any help. |
| Jun14-12, 04:11 PM | #2 |
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Do you need to remove the spectator ions?
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| Jun14-12, 04:13 PM | #3 |
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| Jun14-12, 04:27 PM | #4 |
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Admin
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Chemistry: How do I write an ionic equation for this reaction?
H++OH- - don't you think they will react?
Phosphoric acid is soluble, but it is a weak acid, so it is not dissociated completely. Barium hydroxide is weakly soluble, but it is a strong base, so it is completely dissociated. It is a little bit tricky if you ask me. Not clear to me what they can expect. |
| Jun14-12, 04:31 PM | #5 |
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| Jun14-12, 04:52 PM | #6 |
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Admin
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| Jun14-12, 05:39 PM | #7 |
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| Jun15-12, 01:25 AM | #8 |
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Admin
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The closest would be to assume molecular (undissociated) H3PO4.
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| acids, bases, chemistry, ionic equations |
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