Net Ionic Equation for HC2H3O2 + NH3 Reaction

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In summary, the net ionic equation for the reaction between HC2H3O2 and NH3 is CH3COOH + NH3 → CH3COONH4. To balance the net ionic equation, first write out the balanced molecular equation: HC2H3O2 + NH3 → CH3COONH4. Then, separate the strong electrolytes (HC2H3O2 and NH3) into their respective ions: H+ + C2H3O2- + NH3 → CH3COO- + NH4+. Finally, balance the charges and the number of atoms on each side of the equation to get the net ionic equation: H+ + NH3 → NH4+.
  • #1
Feodalherren
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Homework Statement



What is the net ionic equation for the reaction which takes place when HC2H3O2(aq) is added to NH3(aq)?

Homework Equations





The Attempt at a Solution


I'm confused. How exactly does this thing break apart.

Do I get N(acetate)3 + 4H+?
 
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  • #2
Hint: this is an acid/base reaction.
 

1. What is the net ionic equation for the reaction between HC2H3O2 and NH3?

The net ionic equation for the reaction between HC2H3O2 (acetic acid) and NH3 (ammonia) is CH3COOH + NH3 → CH3COONH4.

2. How do you balance the net ionic equation for HC2H3O2 + NH3?

To balance the net ionic equation, first write out the balanced molecular equation: HC2H3O2 + NH3 → CH3COONH4. Then, separate the strong electrolytes (HC2H3O2 and NH3) into their respective ions: H+ + C2H3O2- + NH3 → CH3COO- + NH4+. Finally, balance the charges and the number of atoms on each side of the equation to get the net ionic equation: H+ + NH3 → NH4+.

3. Is this reaction an acid-base reaction or a redox reaction?

This reaction is an acid-base reaction, as it involves the transfer of a proton (H+) from the acid (HC2H3O2) to the base (NH3).

4. What are the products of the net ionic equation for HC2H3O2 + NH3?

The products of the net ionic equation are the conjugate acid (NH4+) and the conjugate base (CH3COO-) of the reactants HC2H3O2 and NH3.

5. What are the spectator ions in the net ionic equation for HC2H3O2 + NH3?

The spectator ions in the net ionic equation are the ions that do not participate in the reaction and remain unchanged on both sides of the equation. In this case, the spectator ions are C2H3O2- and NH3.

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