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Trouble finding the integral for volumeby Pseudo Statistic
Tags: volumes 
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#1
Feb305, 10:09 AM

P: 390

I'm having trouble finding the integral I'm supposed to use for some Volume problems...
Can someone lead me in the direction as to how I should form my integrals to get the solutions? The below is a scanned page from an AP Calculus textbook, I'm pretty much stumped on how to solve 5659.. Hope someone can help. Thanks. http://www.brokendream.net/xh4/apcalcscan.jpg 


#2
Feb305, 10:47 AM

P: 599

I'll give you some hints on the first one (56a). They're all pretty much the same. The side of the squares are determined by the difference between the two functions y=x+1 and y=x^21. This difference is xx^2+2, it is zero for x=1 and x=2. So now you have determined the shape of your base.
With this you can easily find the area of such a square. Integrating over x gives you the total volume. 


#3
Feb305, 01:36 PM

P: 390

OK, so you merely evaluate the integral [tex]A (x) = \int_{1}^\2 2 x  x^{2} + 2 dx[/tex]?
Does anybody have a clue about the other questions? Thanks. 


#4
Feb405, 01:31 AM

P: 599

Trouble finding the integral for volume
Well, if you want to evalute the area enclosed by the two lines (y=..) yes, but...



#5
Feb405, 03:27 AM

Sci Advisor
HW Helper
P: 2,002

b) Is somewhat easier, since the height of each rectangle is one, that means the area of a cross sectional rectangle is [itex]xx^2+2[/itex]. 


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