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help please, motion of charged particle in mag field |
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| Mar13-05, 03:54 PM | #1 |
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help please, motion of charged particle in mag field
A proton moves in a circular orbit perpendicular to a uniform magnetic field of 0.758T. Find the time it takes the proton to make one pass around the orbit.
Just need someone to help me start off. All I have is that the B=0.758T, q=1.6x10^-19C and m=1.67x10^-27kg. What formulas do I need to use to find t? Thanks |
| Mar13-05, 04:15 PM | #2 |
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U can prove (i advice u to do it) that
[tex] r=\frac{mv}{qB} [/tex] Exploit the connection beteen T,v & r. Daniel. |
| Mar13-05, 04:31 PM | #3 |
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hmm so r=mv/qB is derived from mv^2/r=qvB. I got r=(1.4x10^-8)v. the thing is.. i dont kno the relationship between the time, radius and velocity. Do i use r to find the circumference and multiply that by the velocity? im not really sure..
thanks for the response |
| Mar13-05, 04:49 PM | #4 |
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help please, motion of charged particle in mag field
Yes,that "v" is the constant tangential speed.Multiplied with the period should give exactly 2\pi r...
Daniel. |
| Mar13-05, 04:57 PM | #5 |
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ok i got the correct answer now.. THanks a lot!! :D
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