## help please, motion of charged particle in mag field

A proton moves in a circular orbit perpendicular to a uniform magnetic field of 0.758T. Find the time it takes the proton to make one pass around the orbit.

Just need someone to help me start off. All I have is that the B=0.758T, q=1.6x10^-19C and m=1.67x10^-27kg. What formulas do I need to use to find t?
Thanks

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 Blog Entries: 9 Recognitions: Homework Help Science Advisor U can prove (i advice u to do it) that $$r=\frac{mv}{qB}$$ Exploit the connection beteen T,v & r. Daniel.
 hmm so r=mv/qB is derived from mv^2/r=qvB. I got r=(1.4x10^-8)v. the thing is.. i dont kno the relationship between the time, radius and velocity. Do i use r to find the circumference and multiply that by the velocity? im not really sure.. thanks for the response

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Homework Help

## help please, motion of charged particle in mag field

Yes,that "v" is the constant tangential speed.Multiplied with the period should give exactly 2\pi r...

Daniel.

 ok i got the correct answer now.. THanks a lot!! :D