Formula for potential energy store din a strained solid?

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SUMMARY

The potential energy stored in a strained solid can be calculated using the formula E = λ(Ax²)/(2L), where E is the elastic potential energy, λ is the modulus of elasticity, A is the cross-sectional area, x is the displacement, and L is the natural length. In the case of the scallop's abductin material, with a modulus of 2.20×106 N/m², a thickness of 2.88 mm, and a cross-sectional area of 0.515 cm², the potential energy when compressed 1.19 mm can be determined using this formula. The user initially miscalculated the energy as 23.4075 J due to a computational error, but resolved the issue with further analysis.

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ninjagowoowoo
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formula for potential energy stored in a strained solid??

I was wondering of there was some formula for finding the potential energy stored in a strained/stressed solid. I have this problem:

A scallop forces open its shell with a material called abductin, the elastic modulus of which is about 2.20×106 N/m2. If this piece of abductin is 2.88 mm thick and has a cross-sectional area of 0.515 cm2, how much potential energy does it store when compressed 1.19 mm?

Unfortunately my prof. didnt mention a damned thing about potential energy, so i was wondering if someone could help me out with this... oh yeah and it's not in our book either...
 
Last edited:
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[tex]F = \lambda \frac {Ax}{L} = T[/tex]

F = force, [tex]\lambda[/tex]= modulus of elasticity, A = cross sectional area x = displacement L = natural length T = tension

[tex]E = \int F dx = \lambda \frac {Ax^2}{2L}[/tex]

E = elastic potential energy
 
Wow thanks a bunch. However I'm still not getting the correct answer...

I'm calculating this:


2.20x10^6 * (0.0000515 *(0.00119^2) / 0.00288*2) = 23.4075J which is incorrect.

I got it... turned out to be some weird computational error. Anyway, thanks again !
 
Last edited:

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