- #1
ElBell
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1. Two part question.
An elastic cord with cross sectional area 4.00mm^2 needs a force of 3.6N to increase its length by 12%
Part One- Find the Youngs Modulus of Elasticity
Part Two- The unstretched cord is 0.80m long. Find the energy stored in this strain.
2. Homework Equations :
Y= Stress/ Strain
Stress= Force/ cross sectional area
Strain= change in length/ original length
Part One Attempt-
Stress= 3.6N/ 4* 10^-2
Stress= 90
Strain= 9.6/ 80
Strain= 0.12
Y= 90/ 0.12
Y= 750
Now I don't know what to do! What are the Units? Is this correct?
Part Two Attempt-
I believe this has something to do with Potential Energy...is this correct?
Any help would be much appreciated! Thanks so much for your time
An elastic cord with cross sectional area 4.00mm^2 needs a force of 3.6N to increase its length by 12%
Part One- Find the Youngs Modulus of Elasticity
Part Two- The unstretched cord is 0.80m long. Find the energy stored in this strain.
2. Homework Equations :
Y= Stress/ Strain
Stress= Force/ cross sectional area
Strain= change in length/ original length
Part One Attempt-
Stress= 3.6N/ 4* 10^-2
Stress= 90
Strain= 9.6/ 80
Strain= 0.12
Y= 90/ 0.12
Y= 750
Now I don't know what to do! What are the Units? Is this correct?
Part Two Attempt-
I believe this has something to do with Potential Energy...is this correct?
Any help would be much appreciated! Thanks so much for your time