
#1
Jun105, 08:16 AM

P: 8

I tried doing this but could not,why is it so?




#2
Jun105, 08:33 AM

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It's not difficult.Nobody thought of defining a special function to account for its antiderivative.
Daniel. 



#3
Jun105, 08:34 AM

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Because it can't be integrated in terms of elementary functions. Most functions are 'not easy' to integrate in this way.




#4
Jun105, 09:26 AM

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Thanks
PF Gold
P: 38,886

Why is it difficult to integrate x^x
Or, to say the same thing that Dextercioby and Zurtex said, in different words, because there is no elementary function whose derivative is x^{x}!




#5
Jun105, 10:43 AM

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PF Gold
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A better question would be:
Why is it simple to integrate f(x)=1? 



#6
Jun105, 11:51 AM

P: 70

i tried doin it ,but always get to a place i cant continue.who can help integrate [(x^x)(1+LOG[X])]^2.All help will be appreciated




#7
Jun105, 12:29 PM

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PF Gold
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#8
Jun105, 12:48 PM

P: 23

when i plugged it into the integrator of mathematica it gave it back as same...i dont know why it did not do computation.




#9
Jun105, 01:05 PM

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#10
Jun105, 01:11 PM

P: 23

i understand that yeah...but even Mathematica couldn't post the solution in terms of complex functions or whatever high level function it ocntains...
there must be a solution to it....What it is? 



#11
Jun105, 01:13 PM

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If you want a function that is the antiderivative of x^{x} then just define one and then you can study its properties. 



#12
Jun105, 01:30 PM

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There is a solution it is the function F such that dF/dx is x^x. But we can't write it anymore nicely than that, and there is nothing surprising about it. Almost no functions have integrals that we can write out nicely and explicitly in some closed form. How many times must that be said in this thread? Shall we lock it now to stop yet another person having to say it?




#13
Jun105, 01:56 PM

P: 23

Sorry but i am such a big fool that yours terminology is not clear to me....Last timeHas its integral ever calculated ...or as ppl are saying that it has such a function as integral that has never been defined./so is research going on over this
i have a question......how can we integrate x*Sec(x) i have tried this question than any other question ever..... the point is that it was asked in my 12th class and when i plug it into Integrator i could not even understand the solution... 



#14
Jun105, 02:00 PM

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PF Gold
P: 12,016

Any particular definite integral of x^x can, of course be calculated to an arbitrary degree of accuracy by numerical techniques.




#15
Jun105, 03:16 PM

P: 789

To integrate x*Sec(x) I would use integration by parts, but in this case the tabular method will work nicely.
[tex]\int x\sec{x}dx[/tex] [tex]\int udv = uv  \int vdu[/tex] [tex]u = x[/tex] [tex]dv = \sec{x}dx[/tex] That should get you started. 



#16
Jun105, 05:40 PM

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I think you meant
[tex] dv=\sec x \ dx [/tex] I'm not sure though... Daniel. 


#17
Jun105, 06:02 PM

P: n/a




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