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A car slows down from a speed of 26.0 m/s to rest in 4.50 s. How far did it travel in that time?
What equation do i use?
What equation do i use?
A car decelerates from a speed of 26.0 m/s to rest in 4.50 seconds, resulting in a constant acceleration of -5.78 m/s². To calculate the distance traveled during this time, the formula s = (1/2)at² + v₀t can be utilized, where 'a' is the acceleration, 't' is the time, and 'v₀' is the initial speed. Alternatively, the average speed method can be applied, where the average speed is calculated as the mean of the initial and final speeds, yielding the same distance when multiplied by the time.
PREREQUISITESPhysics students, automotive engineers, and anyone interested in understanding motion dynamics and acceleration calculations.