Car slowing from given speed to rest in given time.

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SUMMARY

A car decelerates from a speed of 26.0 m/s to rest in 4.50 seconds, resulting in a constant acceleration of -5.78 m/s². To calculate the distance traveled during this time, the formula s = (1/2)at² + v₀t can be utilized, where 'a' is the acceleration, 't' is the time, and 'v₀' is the initial speed. Alternatively, the average speed method can be applied, where the average speed is calculated as the mean of the initial and final speeds, yielding the same distance when multiplied by the time.

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A car slows down from a speed of 26.0 m/s to rest in 4.50 s. How far did it travel in that time?
What equation do i use?
 
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Given only the information here, no formula will work. I imagine that you are expected to assume that the car slows down with constant acceleration.

If the car slows from 26.0 m/s to rest (0 m/s) in 4.5 s then its acceleration is (0- 26)/4.5= -5.78 m/s2 (notice the negative- that important!).

Do you know the formula s= (1/2)at2+ v0t? You were given the time, t, and the initial speed v0 and you now know the acceleration, a.

Actually, that's the "hard" way- for this problem you can use the fact that, with a constant acceleration, the "average" speed is just the average of the initial and final speeds. What is the average of 26.0 and 0? If you go at that average speed for 4.5 seconds, how far do you go? Do the problem both ways and compare the answers!
 

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