Multivariable class, we'll be starting curvature

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SUMMARY

The discussion centers on the concept of curvature in multivariable calculus, specifically the formula \(\kappa=|d\phi/ds|\), where \(\phi\) represents the angle between the curve's tangent vector and the horizontal, and \(s\) denotes arc length. The participant expresses difficulty in understanding curvature and seeks clarification on the equation \(\kappa=\frac{|\mathbf{r}'\times\mathbf{r}''|}{|\mathbf{r}'|^{3}}\), which they find more manageable. They also mention the relationship \(\mathbf{r'}=\frac{ds}{dt}\mathbf{T}\) as a helpful insight for simplifying curvature calculations.

PREREQUISITES
  • Understanding of multivariable calculus concepts
  • Familiarity with vector calculus and tangent vectors
  • Knowledge of arc length parameterization
  • Basic proficiency in mathematical notation and equations
NEXT STEPS
  • Study the derivation of curvature formulas in multivariable calculus
  • Learn about the geometric interpretation of curvature
  • Explore the application of curvature in physics and engineering contexts
  • Investigate resources on vector calculus, particularly focusing on tangent vectors and arc length
USEFUL FOR

Students in multivariable calculus, educators teaching curvature concepts, and anyone seeking to deepen their understanding of geometric properties of curves.

FluxCapacitator
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Next week in my multivariable class, we'll be starting curvature, and, nerd that I am, I looked ahead to learn it ahead of time. I can usually at least understand the basics of a new concpet by myself, but curvature really threw me off. Maybe my brain's not right for it, maybe the book sucks, but I know my teacher sucks, so I'm pretty much going to have to learn it myself.

I know that curvature is [itex]\kappa=|d\phi/ds|[/itex], where [itex]\phi[/itex] is the angle between the curve's tangent vector and the horizontal, and s is the arc length.

I also get that the way to do this is to make it [itex]\kappa=|d\phi/dt/(ds/dt)|[/itex], I get lost, however, in actually finding a good equation for [itex]\phi[/itex].

Does anyone have any tips, resources, or advice?
 
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From what I've learned, that equation is hard to work with. Have you seen it as this?:

[tex]\kappa=\frac{|\mathbf{r}'\times\mathbf{r}''|}{|\mathbf{r}'|^{3}}[/tex]

It's much easier to work with (r is the position vector). To show that the two definitions are equal, use the following fact:

[tex]\mathbf{r'}=\frac{ds}{dt}\mathbf{T}[/tex]
 
That's a lot better :D . Thanks! That actually makes sense in a twisted sort of way, and it's a lot easier to use.
 

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