Gas Pressure at 25°C: 0.45 mol, 0.65 L

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SUMMARY

The pressure exerted by 0.450 mol of gas at 25°C in a 0.65 L vessel is calculated using the ideal gas law, resulting in a pressure of approximately 1714.4 kPa. The equation used is derived from the ideal gas law, PV = nRT, and can be rearranged to P = nRT/V for simplicity. This approach streamlines the calculation process, making it more efficient. The discussion confirms the accuracy of the pressure calculation and suggests an optimal method for setting up the equation.

PREREQUISITES
  • Understanding of the Ideal Gas Law (PV = nRT)
  • Basic algebra skills for rearranging equations
  • Familiarity with units of pressure (kPa)
  • Knowledge of gas properties at standard conditions (temperature and volume)
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  • Study the Ideal Gas Law applications in various conditions
  • Learn about the significance of temperature and volume in gas behavior
  • Explore real gas behavior versus ideal gas assumptions
  • Investigate the effects of pressure changes on gas volume
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Chemistry students, physicists, and anyone involved in gas law calculations or thermodynamics will benefit from this discussion.

DB
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what pressure will be exerted by 0.450 mol of a gas at 25 degrees Celsius if it is contained in a vessel wwhose volume is 0.65 L?

[tex]\frac{P_1 * 0.65 L}{298 K * 0.450 mol}=8.31_\frac{L*kPa}{K*mol}[/tex]

[tex]P_1 \sim 1714.4 kPa[/tex]

is this right?
thanks
 
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Yes that is correct although you didn't setup the equation as best you could.

[tex]\frac{{PV}}<br /> {{RT}} = n[/tex]

could have been changed to

[tex]\frac{{nRT}}<br /> {V} = P[/tex]

to make it a much simpler calculation since you are actually looking for P
 
thanks pengwuino, you i know, the simple algebra doesn't bother me tho :)
 

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