Recent content by 21ducks

I am not too good at this, but in the book it says that: The change in an object's momentum divided by the elapsed time equals the constant net force acting on the object. I thought that the grass would slow down the egg, which would mean the interval for stopping is greater making the force...

I just thought the grass might slow it down a bit? Am I wrong?

Homework Statement A moderate force will break an egg. However, an egg dropped on the road usually breaks, while one dropped on the grass usually does not break. This difference is because for the egg dropped on the grass: A- The change in momentum is greater B- The change in momentum is...

So are you saying that the PE = KE? Which would mean KE = 137.2? Just out of curiosity if that is so, what does Vo^2 = ?

Okay so PE = 137.2 right. Now that I know the PE how do I use the equation you mentioned above to obtain the KE? The one I am referring to is: V^2 = Vo^2 - 2g(change in height)?

I think I found it in my book. Is it PE = mgy ? y = 0 right since it is the ground? But won't that just make potential energy equal to 0? I guess I am still a little confused. Thanks for all the help though.

krnhseya So am I using the wrong equation? What equation do you mean that has all of the knowns? <--- I am up for an easier way if there is one. Doesn't all of the potential energy change to kinetic engergy since it is falling and actually moving?

A 7.0 kg bowling ball falls from a 2.0 m high shelf. Just before hitting the floor, what will be its kinetic energy? (g = 9.8 m/s² and assume air resistance is negligible) a. 14 J b. 19.6 J c. 29.4 J d. 137 J Now I tried using the normal Kinetic Energy KE equation KE = 1/2mv² but when...

Perfect! Thank you!

Thanks! So let me see if I understand now. Do I multiply 3.0 X 9.81 = 29.43 for weight and then subtract the tension to get 29.43 - 9.8 = 19.63. Then plug the 19.63 into the Net F/ m = a ?

I have been trying to figure out how this works. I know what the answer is since someone else has previously posted the answer in the forums. I want to learn how to do it though. Here is the question: A 3.0 kg bucket is being lowered by a rope into a 10 m deep well, starting from the top...