Recent content by Abood

I see, thank you very much!

Given: q = 1.6*10^-19 C B = 0.3 T north v = 3*10^6 m/s north-west θ = 37 (degrees) Solution Attempt: a) F = Bqvsinθ = (0.3)(1.6*10^-19)(3*10^6)(sin(37)) = 8.7*10^-14 N b) Via right hand rule, F is into the page c) a = F/m = 8.7*10^-14/1.6 × 10^−27 = 5.4*10^13 m/s^2 When I checked my answers...

My bad... whenever I remember when I played with magnets I always remember trying to force 2 identical poles to touch. Thank you very much for the explanation! I think I understood the question now Since B and C don't attract, they must both be neutral (i.e iron) and that leaves A to be the magnet

I believe that if they have identical poles facing each other, they will repel (N and N or S and S)

If the two magnets were facing each other with opposite poles, they will be attracted to each other and stick. I assumed since B and C don't stick they must be of the same type

I noticed that I posted this question on the wrong section previously by accident and I don't know how to delete it... Sorry for confusing the two sections====== Given: - A sticks to B - B doesn't stick to C My solution: As A sticks to B, one must be a magnet and the other iron. As B doesn't...

Thank you a lot for the very detailed explanation! Think we rushed through the beginning part of the chapter but I feel like I fully grasp the concept now! Thank you very much again for all the help!

Thank you very much for your reply! If I understand correctly now, induction means that the electrons move towards and stay on the edge of the body as long as there is a charged object causing a field, while polarization is when the electrons shift slightly to one side making one side positive...

Hello. Recently we began taking static electricity and our teacher asked us to do a research paper on static electricity and charges in general to help us understand the material better. I've been stuck a bit on trying to understand what's the difference between polarization and induction and...

Oh sorry, was just solving another problem with m = 80 kg. T = 85(15.818) = 1344.53 = 1345 N Ok, now I get it! Thank you very much for your help! It is very appreciated that you spared some time to check my work.

T = ma + mg = 80(5.818+10) = 1265.44 N EDIT: I was wondering how come is Tension opposing the weight since the man is swinging and I didn't see anything say T was opposing W

ac = 5.818 m/s^2 g = 10 Sum of a = 10 - 5.818 = 4.182 m/s^2 downwards Net force = 85*4.182 = 355.47 N downwards What confuses me is how the net force is downwards. Does that mean the weight is too much that the vine will snap?

The 2 forces are gravity (weight) and the Normal force which acts as Tension here but I'm not sure how it should be used

Homework Statement A man, with a mass of 85kg, swings from a vine with a length of 11m. If this speed at the bottom of the swing is 8m/s, what is the tension if g = 10m/s^2? Given: m (mass) = 85kg r (radius) = 11m V (speed) = 8m/s g = 10m/s^2 T = ? Homework Equations Fc (centripetal force) = T...