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The force of the dogs, 6 x 86 N= 516 N divided by the mass of the sled plus the mass of the dogs gives the average acceleration of the sled? So the acceleration of the sled equals the acceleration of the dogs. F=ma a= F/m a= 516 N [fwd]/ 517 kg a= 0.998 m/s2 a= 1.0 m/s2

[b]1. Six dogs, each having a mass of 32 kg, pull a 325 kg sled horizontally across ice. If each dog applies a force of 86 N [fwd], what average acceleration es the sled experience? Assume that friction is negligible. Equation: F=ma My solution: 6 x 86 N= 516 N F=ma a= F/m a=...

Here is the correction: Since R2, R3, R4 and R5 are connected in series, R8 = R2 + R3 + R4 + R5 = 22 Ω + 30 Ω + 27 Ω + 40 Ω = 119 Ω Then R7 and R8 are connected in parallel: 1/R9 = 1/R7 + 1/R8 = 1/20 + 1/119 = 119/2380 + 20/2380 = 139/2380 Ω...

Question 3. Find the total resistance of the following circuit. Formulas: R= V/I If the # of resistors connected in series is n, the equiv. resistor is given by Rs = R1 + R2 +... + Rn likewise with resistors connected in parallel, 1/Rp = 1/R1 + 1/R2 +... + 1/Rn Given: V0 =...

Correct me if I'm wrong, but when the rock hits the ground, wouldn't the speed be zero? It's not moving.

[SOLVED] Help! Total mechanical energy question:) Q. Suppose you are standing on a 30 m building and throw a 1 kg rock upwards at 20 m/s. Knowing that total mechanical energy is conserved, calculate the speed of the rock when it hits the ground. Total Mechanical Energy equation: Etotal...