Question 3. Find the total resistance of the following circuit. Formulas: R= V/I If the # of resistors connected in series is n, the equiv. resistor is given by Rs = R1 + R2 +... + Rn likewise with resistors connected in parallel, 1/Rp = 1/R1 + 1/R2 +... + 1/Rn Given: V0 = 120 V R1 = 20 Ω R2 = 22 Ω R3 = 30 Ω R4 = 27 Ω R5 = 40 Ω R6 = 20 Ω R7 = 20 Ω My attempt: Applying Ohm’s Law to the entire circuit: I0 = V0 / RT , where RT is the total resistance in the circuit But since R3 and R4 are connected in series, RS = R3 + R4 = 30 Ω + 27 Ω = 57 Ω Then RT1 and R7 are connected in parallel: 1/RP = 1/RS + 1/R7 = 1/57 + 1/20 = 20/1140 + 57/1140 = 77/1140 Ω RP = 14.8 Ω = 15 Ω Solve five resistors R1, R2, RP, R5 and R6. These resistors are connected in series RT = R1 + R2 + R3 + R4 + R5 + R6 = 20 Ω + 22 Ω + 15 Ω + 40 Ω + 20 Ω = 117 Ω Therefore, the total resistance of the circuit is 117 Ω. I'm not sure I took the right approach. Any help would be appreciated. Thanks.